Question

completion Status:Will Barclay wishes to determine which antenna he should purchase for his home. The TV store has supplied him with the followinginformation:Range in milesVHF UHFModelPrice3020А$404535B$506040с$607555D$70Will wishes to receive Channel 17 (VHF), which is located 26 miles east and 36 mile north of his home, and Channel 38 (UHF), whichis located 25 miles south and 29 miles west of his home. Which model will allow him to receive both channels at the least cost?(Assume that the terrain between Will's home and both broadcasting stations is flat.)O a..AO b.DOC. BO d.

Answer 1

We need to start by calculating the distances from Will's home to the two stations:

Channel 17 is 26 mi E and 36 N,

so we use the pythagoream theorem to find the distance:

D17^2 = 26^2 + 36^2

then D17 is approximately 44.4 miles from his home

Now Channel 38:

D38^2 = 25^2 + 29^2

then D38 is approximately 38.29 miles from his home

Now looking at the prices and at the ranges:

Recall as well that Channel 17 is (VHF) and Channel 38 is UHF

so he needs at least 44.4 in VHF, and 38.29 in UHF.

Then the cheapest option that covers both conditions is option C.