Question

An old house in Boxerville measures 40 feet in height and has windows 5-feetin width. An architecture student builds a proportional model that is 6-feethigh. How wide are the model's windows, in feet?

Answer 1

`x=0.75\text{ ft}`

Explanation:

To solve for the architectural model, use proportional relationships:

`\begin{gathered} (40)/(5)=(6)/(x);\text{ solve by cross multiplication} \\ x=(6\cdot5)/(40) \\ x=(3)/(4) \\ x=0.75\text{ ft} \end{gathered}`