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Find the measure of MCH.MHDSy + 328y + 19
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Find the measure of MCH.MHDSy + 328y + 19

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I need the picture to answer this question

MCH + HCD = 90°

5y + 32 + 8y + 19 = 90°

13y + 51 = 90

13y = 90 - 51

13y = 39

y = 39/13

y = 3

MCH = 8y + 19 = 8(3) + 19

= 24 + 19

= 43°

User Sparsh Turkane
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