Question

Solve 81x = 27x + 2.( the x and the x+2 are exponents)

Answer 1

Solve the equation below;

`81^x=27^(x+2)`

Step 1: Apply exponent rules

`\begin{gathered} 81^x=27^(x+2) \\ 3^(4x)=3^(3\left(x+2\right)) \end{gathered}`

Step 2: solve for the value of x

`\begin{gathered} 3^(4x)=3^(3\left(x+2\right)) \\ 4x=3\left(x+2\right) \\ 4x=3x+6 \\ 4x-3x=6 \\ x=6 \end{gathered}`

Therefore the value of x = 6