The secondary coil of an ideal transformer has 477 turns, and the primary coil has 75 turns. What is the ratio of the current in the primary coil to the current in the secondary?

My account
Edit my Profile
Private messages
My favorites

Ask a Question
Questions
Unanswered
Tags
Categories
Ask a Question

asked Dec 27, 2023 153k views

5 votes

The secondary coil of an ideal transformer has 477 turns, and the primary coil has 75 turns. What is the ratio of the current in the primary coil to the current in the secondary?

Physics
college

Sahar Millis asked

by Sahar Millis

7.8k points

0 Comments

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

7 votes

The ratio of current is the inverse of the ratio of the voltage and number of turns.

Ip/Is = Ns/Np = 477/75

Ip/Is = 6.36

Stanlekub answered Jan 1, 2024

by Stanlekub

8.2k points

0 Comments

Please log in or register to add a comment.

Ask a Question

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

8.8m questions

11.4m answers

0 Comments

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

0 Comments

Please log in or register to add a comment.

Other Questions