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Given the figure below, find EF if CA = (6n) and EF =

Given the figure below, find EF if CA = (6n) and EF =-example-1

1 Answer

3 votes

Given:


\begin{gathered} CA=6n \\ EF=n+8 \end{gathered}

To find:

The length of EF.

Step-by-step explanation:

According to the figure,

We can write,


(BE)/(BC)=(EF)/(CA)

Substituting the given values, we get


\begin{gathered} (x)/(2x)=(n+8)/(6n) \\ (1)/(2)=(n+8)/(6n) \\ 6n=2n+16 \\ 4n=16 \\ n=4 \end{gathered}

Therefore, the length of EF will be,


EF=n+8=4+8=12

Final answer:

The length of EF will be 12.

User Nicola De Fiorenze
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