Question

Given the figure below, find EF if CA = (6n) and EF =

Answer 1

Given:

`\begin{gathered} CA=6n \\ EF=n+8 \end{gathered}`

To find:

The length of EF.

Step-by-step explanation:

According to the figure,

We can write,

`(BE)/(BC)=(EF)/(CA)`

Substituting the given values, we get

`\begin{gathered} (x)/(2x)=(n+8)/(6n) \\ (1)/(2)=(n+8)/(6n) \\ 6n=2n+16 \\ 4n=16 \\ n=4 \end{gathered}`

Therefore, the length of EF will be,

`EF=n+8=4+8=12`

Final answer:

The length of EF will be 12.