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A line includes the points (1,0) and (2,6). What is the equation in slope-intercept form.

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First, let's calculate the slope of the line:


m=(6-0)/(2-1)\Rightarrow m=6

Let's use a generic slope-intercept equation, the slope we just calculated and point (1, 0) as following:


\begin{gathered} y=mx+b \\ \Rightarrow0=6(1)+b \end{gathered}

Solving for b (the y-intercept):


\begin{gathered} 0=6(1)+b \\ \Rightarrow-6=b \end{gathered}

This way, we can conclude that the equation of the line in the slope-intercept form is:


y=6x-6

User Matthieu Moy
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