Question

If the skater starts at a height of 2m on one side of the ramp and starts to move how high with he get on the the other side.

Answer 1

We are given that a skater starts at a height of 2 meters. If we do a balance of energy and assume that there is no friction or any other nonconservative forces we get:

`\text{mgh}_0=mgh_f`

Where:

`\begin{gathered} m=\text{ mass} \\ g=\text{ acceleration of gravity} \\ h_0,h_f=\text{ initial and final height} \end{gathered}`

We can cancel out the mass and the acceleration of gravity:

`h_0=h_f`

Substituting the initial height we get:

`2m=h_f`

Therefore, on the other side, he will get to 2 meters in height.