Question

the temperature of a sample of water increases from 15.0c to 30c as it absorbs 5000j of heat what is the mass of the sample? specific heat of water is 2.03 j/gc

Answer 1

The formula that relates the heat and the temperature change is:

`Q=mc\Delta T`

Where Q is the heat, m is the mass, c is the specific heat and ΔT is the temperature change.

Since it absorbes heat, the sign of Q is positive, so:

`Q=5000j`

And the change in temperature is:

`\Delta T=T_f-T_i=30\degree C-15.0\degree C=15\degree C`

So, solving the equation for m and substituting the values, we have:

`\begin{gathered} Q=mc\Delta T \\ mc\Delta T=Q \\ m=(Q)/(c\Delta T)=(5000j)/(2.03j/g\degree C\cdot15\degree C)=164.20\ldots.g\approx164g \end{gathered}`

So, the mass of the sample is approximately 164 g.