Data input
hc = Cone height
hd = cylinder height
r = radius
r= 11/2 = 6.5 yd
hc = 9 yd
hd = 13 yd
Procedure
First we will calculate the volume of the cylinder
![\begin{gathered} V=h_d\cdot\pi\cdot r^2 \\ V=13\cdot\pi\cdot6.5^2 \\ V=1724.64\text{ yd}^3 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/zk3vi1kk2dn2j79lwtcvjf5disv3mbd0ww.png)
Second we will calculate the volume of the cone
![\begin{gathered} V=(1)/(3)\pi\cdot r^2\cdot h \\ V=(1)/(3)\cdot\pi\cdot(6.5)^2\cdot9 \\ V=397.99 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/mwxfku2yxqy7dn0gqetlogl9ku79w5u2to.png)
The total volume would be the sum of the two volumes calculated above.
![\begin{gathered} Vt=1724.64+397.99 \\ Vt=2122.63 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/y3owpbau5hug0z6dscuct828s7563epyia.png)
Total volume equals 2122.63 yd^3