Question

Writean equationofthecirclewithcenter(-8,3)andradiusr=4

Answer 1

The general equation of the circle is :

`(x-h)^2+(y-k)^2=r^2`

Where the center at the point ( h , k ) and the radius = r

It is required to find the equation of the circle with center at (-8 , 3) and r = 4

So,

h = -8

k = 3

r = 4

substitute with the previous value at the general equation of the circle

so,

`\begin{gathered} (x-(-8))^2+(y-3)^2=4^2 \\ \\ (x+8)^2+(y-3)^2=16 \end{gathered}`