We have to find the probability of landing on a 4 and then landing on an even number.
We can divide this into two events that both have to happen. They are independent events so we can express this as:
![P(4\&E)=P(4)\cdot P(E)](https://img.qammunity.org/2023/formulas/mathematics/college/4c5gxrdu5ru3r5ycgrn8qjnykqd255y1e7.png)
The probability of obtaining a 4 in the first spin is 1/4 as there is only one successful outcome (getting a 4) out of 4 possible outcomes. All outcomes have the same probability so we don't need to calculate probabilities of each one.
The probability of obtaining an even number in the second spin is 2/4 = 1/2, as we have two successful outcomes (getting a 4 and getting a 6) out of 4 possible outcomes.
Then, we can calculate the probabilty of both events as:
![P(4\&E)=P(4)\cdot P(E)=(1)/(4)\cdot(1)/(2)=(1)/(8)](https://img.qammunity.org/2023/formulas/mathematics/college/4qeez95zd0cjzf472fbcc23c5j3ejvvgfo.png)
Answer: The probability is 1/8.