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Reduce the rational expression to lowest terms. If it is already in lowest terms, enter the expression in the answer box. Also, specify any restrictions on the variable.(a − 1)²(a - 5)/(a - 5)²(a - 1)Rational expression in lowest terms:Variable restrictions for the original expression: a

Reduce the rational expression to lowest terms. If it is already in lowest terms, enter-example-1

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We have the following rational expression:


((a-1)^2(a-5))/((a-5)^2(a-1))

And we have to reduce the expression to the lowest terms.

1. To achieve that, we can see that:

• There are two common factors:


(a-1)\text{ and }(a-5)

2. Now, we know that:


\begin{gathered} a^2=a*a \\ \\ \text{ And also, we have that:} \\ \\ (a)/(a)=(b)/(b)=1 \end{gathered}

3. And we can apply the same rule for the given case as follows:


\begin{gathered} ((a-1)^(2)(a-5))/((a-5)^(2)(a-1))\Rightarrow(a-1)^2=(a-1)(a-1),(a-5)^2=(a-5)(a-5) \\ \\ \text{ Then we have:} \\ \\ ((a-1)(a-1)(a-5))/((a-5)(a-5)(a-1)) \end{gathered}

4. And we can rewrite the expression as follows:


\begin{gathered} ((a-1)(a-1)(a-5))/((a-5)(a-5)(a-1))=((a-1))/((a-1))((a-5))/((a-5))((a-1))/((a-5))\Rightarrow((a-1))/((a-1))=1,((a-5))/((a-5))=1 \\ \\ \text{ Then we have:} \\ \\ ((a-1)(a-1)(a-5))/((a-5)(a-5)(a-1))=(1)(1)((a-1))/((a-5))=((a-1))/((a-5)) \\ \\ \end{gathered}

Therefore, the rational expression of the lowest terms is:


(a-1)/(a-5)

5. We can determine that the variable restrictions for the original expression can be found as follows:


\begin{gathered} ((a-1)^(2)(a-5))/((a-5)^(2)(a-1)) \\ \\ \text{ If a = 5, then we would have:} \\ \\ ((a-1)^2(5-5))/((5-5)^2(a-1))=(0)/(0)\rightarrow\text{ This is NOT defined. Then a}\\e5 \end{gathered}


\begin{gathered} ((a-1)^(2)(a-5))/((a-5)^(2)(a-1)) \\ \\ \text{ If a = 1, then we have:} \\ \\ ((1-1)^2(a-5))/((a-5)^2(1-1))=(0)/(0)\rightarrow\text{ This is NOT defined. Then a}\\e1 \end{gathered}

Therefore, in summary, we have that:

• The rational expression in the lowest terms is:


(a-1)/(a-5)

• The variable restrictions for the original expression:


a\\e1,5

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