Question

In ∆PQR, p= 6.7 inches, r=2 inches and

Answer 1

The Law of sines states:

`(\sin (\angle P))/(p)=(\sin (\angle R))/(r)`

Substituting with data, and solving for angle P, we get:

`\begin{gathered} (\sin(\angle P))/(2)=(\sin(142))/(6.7) \\ (\sin(\angle P))/(2)=(0.615)/(6.7) \\ \sin (\angle P)=0.091\cdot2 \\ \angle P=\arcsin (0.182) \\ \angle P=10.6\text{ \degree} \end{gathered}`