Question

Solve the following quadratic equation by using formula. If needed , submitted your answer as a fraction reduced lowest terms.

Answer 1

We need to find the solution to the equation

`3y^(2)-7y=0`

Step 1

Rewrite the expression on the left side, grouping the common factor, as follows:

`\begin{gathered} 3y\cdot y-7y=0 \\ \\ y(3y-7)=0 \end{gathered}`

Step 2

Notice that the above equation holds when one of the factors is zero:

`\begin{gathered} y=0 \\ or \\ 3y-7=0 \\ 3y=7 \\ y=(7)/(3) \end{gathered}`

Answer

Since both 0 and 7/3 are already reduced to the lowest terms, the answer is

`\begin{gathered} y=0 \\ or \\ y=(7)/(3) \end{gathered}`