Answer: 3 and 2
First, find the derivative of the given function


Next, solve for x

*Factor out 6 and equate to 0


*Divide both sides by 6.

*Set x - 3 = 0


*Set x - 2 = 0


Next, substitute these x values to the original function.
* x = 3






* x = 2





We now have a set of critical points
( 3, 27 ) and ( 2, 28 )
The critical values of x would be 3 and 2.