D is the answer.
The general equation of a line is given as y = mx + c where
m is the gradient, in this case, we can get it at the points (x,y) for 1 and 2 at (0,-4) and (6, 0)
![m\text{ =}\frac{y_2-y_{1_{}}}{x_2-x_1}=(0-(-4))/(6-0)=(4)/(6)=(2)/(3)](https://img.qammunity.org/2023/formulas/mathematics/college/acdockviushkwvk3gpocimk8ad1kf6ep92.png)
and
c is the intercept on the y-axis clearly seen to cut the y axis at -4
We have the equation to be y = 2x/3 - 4
Thus ratifying our answer.
D is the answer.