Question

An engineer is designing a runway. The lowest acceleration for the plane is 3 m/s2. The take-off speed is 65 m/s, what is the minimum allowed length of runway?

Answer 1

`704.2\text{ m}`

Step-by-step explanation

To find the minimum allowed length of the runway, we have to apply one of Newton's equations of motion:

`v^2=u^2+2as`

where v = final velocity = 65 m/s

u = initial velocity = 0 m/s

a = acceleration = 3 m/s^2

s = distance/length = ?

We need to solve for s. That is:

`\begin{gathered} 65^2=0^2+2\cdot3\cdot s \\ \Rightarrow6s=4225 \\ \Rightarrow s=(4225)/(6) \\ s\approx704.2\text{ m} \end{gathered}`

That is the minimum allowed length of the runway.