The R-value of a given material is given by the following formula:
![R=(L)/(k)](https://img.qammunity.org/2023/formulas/physics/college/43rlyrro5y0c0mviers1il7d9gj46ueha1.png)
Where:
![\begin{gathered} R=\text{ R-value} \\ L=\text{ thickness} \\ k=\text{ thermal conductivity} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/4zjzmkd3lrx2ah9qxggplz9xygc2swho5a.png)
The thermal conductivity is a property of the material, in the case of the common building brick it is:
![k=0.347\frac{Btu}{ft\text{ h F}}](https://img.qammunity.org/2023/formulas/physics/college/zblgm9krfbh9zyvdavi1kzdyhpjcav1vkm.png)
Before we determine the R-value we will convert the thickness from 3.3 inches to feet using the following conversion factor:
![1ft=12\text{in}](https://img.qammunity.org/2023/formulas/physics/college/756op63zamihedbmsuhymfuqj5afh26i72.png)
Multiplying by the conversion factor:
![3.3in*(1ft)/(12in)=0.275ft](https://img.qammunity.org/2023/formulas/physics/college/p0h5hu5sognxn9hktnc2tc0n5an3hkfeoc.png)
Now, we plug in the value in the formula for the R-value:
![R=\frac{0.275ft}{0.347\frac{Btu}{ft\text{ h F}}}](https://img.qammunity.org/2023/formulas/physics/college/afi13zd55m6xsyvj4g74wkehy732w4sxe8.png)
Solving the operations:
![R=0.79\frac{ft^2\text{ h F}}{Btu}](https://img.qammunity.org/2023/formulas/physics/college/9zvrftqufn2iglbuxw9rs50j65sqgkw14k.png)
Therefore, the R-value is 0.79