![\text{the quotient }\frac{20}{\sqrt[]{16}}\text{ is an rational number}](https://img.qammunity.org/2023/formulas/mathematics/high-school/pgqmtzd25cml3rse2mfmzm7ab849pratfu.png)
because, the quotient has an integer in its denominator
Step-by-step explanation
A rational number is a number that is expressed as the ratio of two integers

hence
for

we can solve the root in the denominator, so we have
![\begin{gathered} (20)/(√(16)) \\ \frac{20}{\sqrt[]{16}}=(20)/(4) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/uuorq97vbveoilzf3ad87jw481fpifk6uy.png)
so, as the number can be expressed as the ratio of two integers ( 20 and 4) we can conclude
![\text{the quotient }\frac{20}{\sqrt[]{16}}\text{ is a rational number}](https://img.qammunity.org/2023/formulas/mathematics/high-school/xjwswonq257gb5cl83gupbipyr6nkc4pg6.png)
because, the quotient has an integer in its denominator
I hope this helps you