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I need help finding the correlation coefficient I got everything else

I need help finding the correlation coefficient I got everything else-example-1
I need help finding the correlation coefficient I got everything else-example-1
I need help finding the correlation coefficient I got everything else-example-2
User Skarab
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From the given table, the equation of the line of best fit is:


y=13.98x+478.73

where x denotes the years and y the number of students.

Now, the mean of the y-values is


\mu_y=(5556)/(10)=555.6

The variance of y-values is given by


\text{SSy}=\Sigma(y-\mu_y)^2

By expanding this sum, we have


\text{SSy}=(492-555.6)^2+(507-555.6)^2+(520-555.6)^2+\ldots+(618-555.6)^2

which gives


\text{SSy}=16118.4

By doind the same process for the varible x, we have that the correlation coefficient R is given by:


R=0.9999

since this result is near to 1, there is a strong positive relationship between the year and the number of students

I need help finding the correlation coefficient I got everything else-example-1
User Ilario Engler
by
7.7k points

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