Question

12. You have 8.1 x10^24 particles of CAH&O4. How many grams are present?

Answer 1

In this question, we have 8.1*10^24 particles of C4H8O4, we need to find the number of moles present in this amount of particles:

1 mol = 6.022*10^23

x moles = 8.1*10^24

x = 13.45 moles of C4H8O4

Now using its molar mass, 120.1g/mol, we will find the final mass:

120.1g = 1 mol

x grams = 13.45 moles

x = 1615 grams of C4H8O4