Question

27. Morgan and Kendall began joggingat the same location and jogged inopposite directions. Morgan's rate was1 mph faster than Kendall's rate. Aftertwo hours they were 21 miles apart.Find the rate of each.

Answer 1

We will have the following:

First, we have that the rates for Morgan and Kendall will be the following (Respectively):

`r_1=v+1`

&

`r_2=v`

And the distance will be given by:

`d=((r_1+1)+(r_2))\cdot t`

Here "t" is the time.

Now, we replace the values and solve for the rate "v":

`21=((v+1)+v)\cdot2\Rightarrow21=(2v+1)\cdot2`
`\Rightarrow2v+1=(21)/(2)\Rightarrow2v=(19)/(2)`
`\Rightarrow v=(19)/(4)`

So, Morgan and Kendall's rates are respectively:

`M=(23)/(4)\cdot(m)/(h)`

&

`K=(19)/(4)\cdot(m)/(h)`