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Solve for the variable:4z−2z(1+4)–36 for z=5
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Solve for the variable:4z−2z(1+4)–36 for z=5

User Simonwo
by
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1 Answer

6 votes

Given:

4z-2z(1+4)-36 for z=5

4z-2z(1+4)-36=4(5)-2(5)(5)-36

=20-50-36

=-66

User BizarroDavid
by
6.5k points
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