Question

What is the equation of the line that passes through the point (-4, 6) and has aslope of -5/4

Answer 1

We have the following:

`y=mx+b`

where m is the slope and b is the y-intercept

now, for b, the line passes through the point (-4, 6)

therefore, x = -4 and y = 6

replacing:

`\begin{gathered} 6=-(5)/(4)\cdot-4+b \\ 6=5+b \\ b=1 \end{gathered}`

Therefore, the equation is:

`y=-(5)/(4)x+1`

check:

`\begin{gathered} y=-(5)/(4)+-4+1 \\ y=5+1 \\ y=6 \end{gathered}`