Question

This one is super hard

Answer 1

`\begin{gathered} \text{Answer} \\ \log _b6 \end{gathered}`

Step-by-step explanation

According to the laws of logarithms

`\begin{gathered} \text{Log}_ax+log_aY=log_aXY \\ \text{Therefore, } \\ \log _b2+log_b\text{ 3} \\ =log_b\text{ (2 x 3)} \\ =log_b6 \end{gathered}`