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5 votes
This one is super hard

1 Answer

4 votes

\begin{gathered} \text{Answer} \\ \log _b6 \end{gathered}

Step-by-step explanation

According to the laws of logarithms


\begin{gathered} \text{Log}_ax+log_aY=log_aXY \\ \text{Therefore, } \\ \log _b2+log_b\text{ 3} \\ =log_b\text{ (2 x 3)} \\ =log_b6 \end{gathered}

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