Question

In need help! This homework is due in 20 minutes

Answer 1

The final volume, V₂ the gas occupies = 8.81 L

Step-by-step explanation

Given data:

Initial temperature, T₁ = 31 °C = 31 +273 K = 304 K

Initial volume, V₁ = 7.74 L

Final temperature, T₂ = 73 °C = 73 + 273 K = 346 K

Note: The pressure is kept constant.

What to find:

The final volume, V₂ the gas occupies.

Step-by-step solution

Using Charle's law:

`(V_1)/(T_1)=(V_2)/(T_2)`

To get V₂, substitute the given parameters into the equation above:

`\begin{gathered} \frac{7.74\text{ L}}{304\text{ K}}=\frac{V_2}{346\text{ K}} \\ \text{Cross multiply} \\ V_2*304\text{ K }=7.74\text{ L }*346\text{ K} \\ \text{Divide both sides by 304 K} \\ \frac{V_2*304\text{ K }}{304\text{ K }}=\frac{7.74\text{ L }*346\text{ K}}{304\text{ K }} \\ V_2=8.81\text{ L} \end{gathered}`

The final volume, V₂ the gas occupies is 8.81 L