The sample is given

First determine the mean of the sample,
The total number of masses are 9.
Then mean is calculated as sum of all the masses divided by total number of masses.


The mean obtained is 37.39572.
To determine the standard deviation , use the formula.
![\sigma=\sqrt[]{(1)/(N)\Sigma(x_i-\mu)^2}](https://img.qammunity.org/2023/formulas/mathematics/college/9gkn6b8xebzf4b5dujfsu5tya7x33x5u5n.png)
Now we have to evaluate the value of summation in the square root.
Now substitute the value in standard deviation formula
![\sigma=\sqrt[]{(1)/(9)(0.0520756928)}=\sqrt[]{0.0057861880888}=0.076066997](https://img.qammunity.org/2023/formulas/mathematics/college/swaqzmb3pared14jbjem17di5ee0wj49n3.png)
Hence the standard deviation of the masses given is 0.076066997.