Question

1. How much Heat is released when 5 grams of Ethanol (C2H5OH) reacts with excess02 in the following equation?C2H5OH + 302 --> 2CO2 + 3H2OH = -1,400 kJ

Answer 1

-151.94kJ

Explanations:

Given the chemical reaction

`C_2H_5OH+3O_2\rightarrow2CO_2+3H_2O\text{ }\triangle H=-1400kJ`

According to the given equation, 1 mole of ethanol will release 1400kJ.

Determine the mole of 5 grams of Ethanol

`\begin{gathered} mole\text{ of ethanol}=\frac{5g}{46.07\text{g/mol}} \\ mole\text{ of ethanol}=0.1085moles \end{gathered}`

The amount of energy the 0.1085moles of ethanol will release is be expressed as:

`\begin{gathered} energy\text{ released}=0.1085*-1400 \\ energy\text{ released}=-151.94kJ \end{gathered}`