Assume you have a normal distribution with a mean of 75 and a standard deviation of 14. Find the Z-Score of 62, rounding your answer to the nearest HUNDREDTH.

Question

asked Jun 19, 2023 52.5k views

1 Answer

Fahu · Answer 1 · 2023-06-25T10:07:38+0000

STEP - BY - STEP EXPLANATION

What to find?

The z-score of 62

Given:

mean(μ) = 75

Standard deviation (σ) = 14

x- = 62

Step 1

Recall the formula for z - score.

$Z=(x-\mu)/(\sigma)$

Step 2

Substitute the values into the formula and simpl

$\approx-0.93$

ANSWER

-0.93