Question

Someone please help I’m been on this question for a hour

Answer 1

Given the information in the image on the question tab;

We have to form triangles using points A and B, and points A and C;

Then find the slopes between A and B, and A and C;

Part A;

`\begin{gathered} Slope\text{ between point A and B is:} \\ (AM)/(BM)=(147-105)/(2-1)=(42)/(1)=42 \end{gathered}`
`\begin{gathered} Slope\text{ between point A and C is:} \\ (AN)/(CN)=(147-63)/(2-0)=(84)/(2)=42 \end{gathered}`

The slopes are equal.

Part B;

`The\text{ initial value of the graph is 63m}`

The initial value, or y-intercept, is the output value when the input of a linear function is zero. It is the y-value of the point at which the line crosses the y-axis.

`The\text{ slope of the graph is 42.}`

The slope represents change in y over change in x. Therefore, in a distance vs. time graph, the slope is equal to distance/time, which represents the velocity.