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Graph ABCD with B(0, 6). C(2. -5). D(-8, -1), then order the angle measures from least to greatest.

Graph ABCD with B(0, 6). C(2. -5). D(-8, -1), then order the angle measures from least-example-1
User Deep Arora
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1 Answer

3 votes

the measure of the angle from least to greatest

Step-by-step explanation:

B(0, 6)

C(2. -5)

D(-8, -1)

Plotting the points on a graph:

To determine the angles from the least to the greatest, we need to find the distance between the points.

distance formula:


dis\tan ce\text{ = }\sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2}
\begin{gathered} \text{Distance BC = }\sqrt[]{(-5_{}-6)^2+(2_{}-0)^2} \\ =\text{ }\sqrt[]{(-11)^2+(2)^2}\text{ = }\sqrt[]{121\text{ + 4}}\text{ = }\sqrt[]{125\text{ }} \\ \text{Distance BC = 1}1.18 \end{gathered}
\begin{gathered} x_1=2,y_1=-5,x_2=-8,y_2\text{ = -1} \\ \text{Distance CD = }\sqrt[]{(-1-(_{}-5))^2+(-8_{}-2)^2} \\ \text{Distance CD = }\sqrt[]{(-1+5)^2+\mleft(-10\mright)^2} \\ =\text{ }\sqrt[]{(4)^2+100}\text{ = }\sqrt[]{116} \\ \text{Distance CD = 10.77} \end{gathered}
\begin{gathered} x_1=0,y_1=6,x_2=-8,y_2\text{ = -1} \\ \text{Distance BD = }\sqrt[]{(-1-_{}6)^2+(-8_{}-0)^2} \\ =\sqrt[]{(-7)^2+(-8)^2\text{ }}\text{ = }\sqrt[]{49\text{ + 64}}\text{ = }\sqrt[]{113} \\ \text{Distance BD= }10.63 \end{gathered}

The higher the length, the higher the angle

BC > CD and CD > BD

From the least to the greatest, the distance between the points are:

BD, CD, BC

The angles are opposite the distance and corresponds to each other

Following the arrangement of the distance,

Hence, the measure of the angle from least to greatest

Graph ABCD with B(0, 6). C(2. -5). D(-8, -1), then order the angle measures from least-example-1
Graph ABCD with B(0, 6). C(2. -5). D(-8, -1), then order the angle measures from least-example-2
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