72.2k views
2 votes
Given A be busy prove

Given A be busy prove-example-1
User Tim Specht
by
8.1k points

1 Answer

1 vote

We can solve this question if we have that the sum of the interior angles of a triangle is 180 degrees.

We have:

Statement-------------------------------------Reasons

The sum of the interior angles of a triangle is equal to 180 degrees. Then, we have:


m\angle A+m\angle B+m\angle C=180

Then, we have that m∠B = 90° (since AB is perpendicular to BC). Then, we have:


m\angle A+90^(\circ)+m\angle C=180

Subtracting 90° from both sides of the equation, we have:


m\angle A+90^(\circ)-90^(\circ)+m\angle C=180^(\circ)-90^(\circ)

Finally


m\angle A+m\angle C=90^(\circ)

Therefore,

[We have from your homework: "If two angles form a right angle (90°), then they are complementary.]

Given A be busy prove-example-1
User Yong Jie Wong
by
8.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories