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Given A be busy prove

Given A be busy prove-example-1
User Tim Specht
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1 Answer

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We can solve this question if we have that the sum of the interior angles of a triangle is 180 degrees.

We have:

Statement-------------------------------------Reasons

The sum of the interior angles of a triangle is equal to 180 degrees. Then, we have:


m\angle A+m\angle B+m\angle C=180

Then, we have that m∠B = 90° (since AB is perpendicular to BC). Then, we have:


m\angle A+90^(\circ)+m\angle C=180

Subtracting 90° from both sides of the equation, we have:


m\angle A+90^(\circ)-90^(\circ)+m\angle C=180^(\circ)-90^(\circ)

Finally


m\angle A+m\angle C=90^(\circ)

Therefore,

[We have from your homework: "If two angles form a right angle (90°), then they are complementary.]

Given A be busy prove-example-1
User Yong Jie Wong
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4.3k points