In this question, we are not given the function /equation, however, we are to find the funtion that takes real numbers x :
so, we will map all subset of the set R of all real numbers into R
lets take :
f(x) = 2(x) , where x= 0; +_1; +_2; +-3.....is a mapping of R of all intergers
(a) Multipy by -1
f(x) = -2x
(b)Add 1
f(x) = 2x +1
(c) square root
f(x) = √(2x+1)
(d) take reciprocal
x =√(2y +1) ... solve for y
y ^-1 = (x^2 -1) /2
expression for f (x) = √(2x+1)
Domain : x ≥-1/2
interval notation :[-1/2 ; ∞)