Question

What volume of a 3.00M KI stock solution would you use to make 0.300 L of a 1.25M KI solution?

Answer 1

0.125L

Explanations:

According to the dilution formula

`C_1V_1=C_2V_2`

where:

• C1 and C2 are the ,concentrations

,

• V1 and V2 are the, volumes

Given the following parameters

`\begin{gathered} C_1=3.00M \\ C_2=1.25M \\ V_2=0.300L \end{gathered}`

Requuired

Iniital volume V1

Substitute

`\begin{gathered} V_1=(C_2V_2)/(C_1) \\ V_1=(1.25*0.3)/(3.0) \\ V_1=0.125L \end{gathered}`

Therefore the amount of volume required is 0.125L