Question

Jamie is practicing for the long jump each week she makes 10 jumps in after each jump she recorded the centimeters he reaches with each jump results for this week are represented in the table below Jamie then reviews for results in the term is the mean and standard deviation so that she can compare her results for this week to her results from the previous week Jaime Felt her 10th jumpers not reflect his of her ability because she stumbled before making the jump and decided to remove the 10th to jump from her data set determine whether each statement describes a change that will occur to the mean and standard deviation for the week results when Jamie remove the tenths to jump from her data set select yes or no for each statement

Answer 1

First question

with the 10th term

`\text{average}=(5.1+5.3+5.4+5.2+5.5+5.4+5.2+5.3+5.5+3.5)/(10)=5.1`

without the 10th term

`\text{average}=(5.1+5.3+5.4+5.2+5.5+5.4+5.2+5.3+5.5)/(9)=5.3`

so the answer is YES

Second question. the answer as we can see doing the first question is NO

Third question

The more spread out a data distribution is, the greater its standard deviation

so the answer is YES

Fourth question

for the same reason above in the third question the answer is YES