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7. At what temperature will 0.554 moles of neon gas occupy 22.9 Lat 1.95 atm?

User Kyriakos
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1 Answer

3 votes

Answer:


981.79\text{ K}

Step-by-step explanation:

Here, we want to get the temperature at which the given number of moles would be occupied

To get this, we shall use the ideal gas equation

Mathematically:


\begin{gathered} PV\text{ = nRT} \\ T\text{ = }(PV)/(nR) \end{gathered}

where:

P is the pressure given as 1.95 atm

V is the volume, given as 22.9 L

n is the number of moles, given as 0.554 moles

R is the molar gas constant which is 0.0821 L.atm/mol.K

T is the temperature which we want to calculate

Substituting the values, we have it that:


T\text{ = }(1.95*22.9)/(0.554*0.0821)\text{ = 981.79 K}

User MrBliz
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