Question

A 0.50 kg softball is thrown vertically with a velocity of 30 m/s. What is the maximum height that the ball will reach?46 m15 m7.5 m92 m

Answer 1

The maximum height reached by the ball is 46 m.

Given data:

The mass of the ball is m=0.50 kg.

The velocity of the ball is v=30 m/s.

The gravitational acceleration acting on the ball is g=9.8 m/s².

The maximum height that the ball reach will be,

`\begin{gathered} h_(max)=(v^2)/(2g) \\ h_(max)=((30)^2)/(2(9.8)) \\ h_(max)=46\text{ m} \end{gathered}`

Thus, the maximum height reached by the ball is 46 m.