Looking at the height values, we can see that the values are being multiplied by a constant value (we have a geometric sequence).
To find the common ratio, let's divide one term by the term before.
Using bounces 2 and 1, we have:
![q=(2560)/(10240)=(1)/(4)](https://img.qammunity.org/2023/formulas/mathematics/college/w0k7789pd12v6nxzaaeop63lg2947fafgk.png)
The recursive formula relates one element of the sequence with the previous element,
Since each value in the table is 4 times less than the value before, we can write the recursive formula below:
![a_n=a_(n-1)\cdot(1)/(4)](https://img.qammunity.org/2023/formulas/mathematics/college/7syz85u1mmir9f5eztq7hvzjtlomurdvg3.png)
To write an explicit formula, we can use the model below:
![a_n=a_1\cdot q^(n-1)](https://img.qammunity.org/2023/formulas/mathematics/college/rlg5kaxmt1mz5h3g1qfct43fvqd76l4l78.png)
Since the first term is 10240, we have a1 = 10240, so the formula is:
![a_n=10240\cdot((1)/(4))^(n-1)](https://img.qammunity.org/2023/formulas/mathematics/college/hpiukg8ycxeivenebe222s3insqc3nal7k.png)
To find the height at bounce 8, let's use n = 8 and calculate the value of a8:
![\begin{gathered} a_8=10240\cdot((1)/(4))^(8-1) \\ a_8=10240\cdot((1)/(4))^7 \\ a_8=0.625 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/u8h1pmtzgav13repdt92hqbbw1mne2fm8e.png)
Therefore the height after bounce 8 is equal to 0.625 cm.