We know that in a collision the momentum of the system is conserved, that is:
![p_i=p_f](https://img.qammunity.org/2023/formulas/physics/college/e7rj8yeigkhgmt4s6ul64ny08zwwhw91ko.png)
In this case, since the railroad cars coupled together and have the same mass we have:
![mv_1+mu_1=2mv](https://img.qammunity.org/2023/formulas/physics/college/qnlxhacoxhjkzk4c0i3q6rzpygjlwqgyii.png)
Now, we know the initial velocity of the cars, one is traveling at 5 m/s and the other is at rest; plugging the values and solving for the final velocity we have:
![\begin{gathered} 20000(5)+20000(0)=2(20000)v \\ v=(5(20000))/(2(20000)) \\ v=2.5 \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/n14cbsnyek0t547pfma72p1bww99foba39.png)
Therefore, the velocity of the combined cars is 2.5 m/s