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A principal of $2900 is invested at 3% interest, compounded annually. How many years will it take to accumulate $4000 or more in the account? (Use the calculator provided if necessary.)Write the smallest possible whole number answer.

User Pamil
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1 Answer

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To solve this problem, we will use the following formula for annually compounded interest:


A=P(1+r)^t,

where r is the rate of interest in decimal form, t is the number of years, and P is the initial amount.

Substituting P=2900, A=4000, r=0.03 in the formula, we get:


\begin{gathered} 4000=2900(1+0.03)^t=2900(1.03)^t, \\ (4000)/(2900)=1.03^t. \end{gathered}

Applying log to both sides of the equation we get:


log((40)/(29))=tlog1.03.

Therefore:


t=(log(40)/(29))/(log1.03)\approx10.88\text{ years.}

Rounding the smallest possible whole number, we get:


t=11\text{ years.}

Answer:


11\text{ years.}

User Mohabbati
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