Question

Given J(- 2, 5) and K(6, - 3) , find point P on JK such that the partitioned ratio is 2:2

Answer 1

Given J(- 2, 5) and K(6, - 3)

rise = y2 - y1 = -3 - 5 = -8

run = x2 - x1 = 6 - (-2) = 8

ratio = 2:2

c = 2/(2+2) = 2/4 = 1/2

x-coordinate of P: x1 + c*run = -2 + 1/2(8) = 2

y-coordinate of P: y1 + c*rise = 5 + 1/2(-8) = 1

P is located at (2, 1)