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2. Is the vertex a maximum or a minimum? y = -1? + 6x = 9

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You have the following function:


y=-x^2+6x

the general form of a quadratic function is given by:


y=ax^2+bx+c

By comparing the given function with the general form of a quadratic function, you have that a=-1 anf b=6.

The x coordinate of the vertex of a quadractic function can be obained by using the following formula:


x=-(b)/(2a)

By replacing you obtain:


x=-(6)/(2(-1))=3

Thus, the y cooridante of the vertex is:


y=-(3)^2+6(3)=-9+18=9

Then, the vertex is (3,9)

The previous point is a maximum of the function. It can be appreciated in the fact that the dominant term is negative in the function. This makes that for larger values of x the function tends to - infinity and so, the vertex is a a maximum.

User Shoumikhin
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