1 Answer

Arnaud Fouchet · Answer 1 · 2023-03-22T12:41:07+0000

This seems to be a problem of arc length. Let me show you ...

In this case, the minute hand goes from 0 to 15min, so theta would be 90°

We are told that the length of the minute hand is 3.6 cm = r

Thus, S which is the distance that the tip of the minute hand travels, is...

$\begin{gathered} S=2\pi r\cdot(\theta)/(360) \\ S=2\cdot\pi\cdot(3.6)\cdot(90)/(360) \\ S=(9)/(5)\pi \end{gathered}$

S is approximately 5.65 cm

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