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User Subimage
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The given figure can be divided into a square, an isosceles trapezoid, and a semi-circle. Let's find the area of each part


\begin{gathered} A_{\text{square}}=13^2=169in^2 \\ A_{\text{trapezoid}}=((B+b)\cdot h)/(2)=((30+13)\cdot20)/(2)=430in^2 \\ A_(circle)=(\pi(r)^2)/(2)\approx(3.14\cdot15^2)/(2)\approx353.25in^2 \end{gathered}

At last, we add all three areas


A=169+430+353.25=952.3in^2

Hence, the total area is 952.3 square inches.

User Mehdi Sakout
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