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100 POINTS!!!!!

Two cylinders are similar with diameters 6 in and 9 in.
a. Find the ratio of the circumference of their bases


b. Find the ratio of the surface areas.



c. Find the ratio of the volumes.

User Niall Byrne
by
3.1k points

2 Answers

25 votes
25 votes

d=6in,9in

r=3in,4.5in

circumference:-


\\ \sf\longmapsto (2\pi r_1)/(2\pi r_2)


\\ \sf\longmapsto (6\pi)/(9\pi)


\\ \sf\longmapsto (2)/(3)


\\ \sf\longmapsto 2:3

LSA:-


\\ \sf\longmapsto (2\pi r_1h)/(2\pi r_2h)


\\ \sf\longmapsto (6)/(9)


\\ \sf\longmapsto (2)/(3)


\\ \sf\longmapsto 2:3

TSA


\\ \sf\longmapsto (2\pi r_1(h+r_1))/(2\pi r_2(h+r_2))


\\ \sf\longmapsto (6(h+6))/(9(h+9))


\\ \sf\longmapsto (6h+36)/(9h+81)


\\ \sf\longmapsto (h(6+36))/(h(9+81))


\\ \sf\longmapsto (42)/(90)


\\ \sf\longmapsto (7)/(15)


\\ \sf\longmapsto 7:15

Volume:-


\\ \sf\longmapsto (\pi r_1^2h)/(\pi r_2^2h)


\\ \sf\longmapsto (3^2)/(4.5^2)


\\ \sf\longmapsto (9)/(20.25)


\\ \sf\longmapsto 4:9

User Nizzle
by
3.3k points
20 votes
20 votes

Answer:

a. Ratio of their circumference = 2:3

b. The ratio of their surface areas = 2:3

c. The ratio of their volume = 4:9

Explanation:

Let the cylinders be labelled as A and B respectively.

Diameter of cylinder A = 6 in,

its radius =
(diameter)/(2)

=
(6)/(2) = 3 in

Diameter of cylinder B = 9 in,

its radius =
(diameter)/(2)

=
(9)/(2) = 4.5 in

Thus,

a. circumference of a circle = 2
\pir

Circumference of cylinder A = 2
\pir

= 2 x
\pi x 3

= 6
\pi in

Circumference of cylinder B = 2
\pir

= 2 x
\pi x 4.5

= 9
\pi

Ratio of their circumference =
(circumference of cylinder A)/(circumference of cylinder B)

=
(6\pi )/(9\pi )

= 2:3

b. The surface area of a cylinder = 2
\pirh

the surface area of cylinder A = 2
\pirh

= 6
\pih

the surface area of cylinder B = 2
\pirh

= 9
\pih

The ratio of their surface areas =
(surface area of cylinder A)/(surface area of cylinder B)

=
(6\pi h)/(9\pi h)

= 2:3

c. Volume of a cylinder =
\pi
r^(2)h

volume of cylinder A =
\pi
r^(2)h

=
\pi x
3^(2) x h

= 9
\pih

volume of cylinder b =
\pi
r^(2)h

=
\pi x
4.5^(2) x h

= 20.25
\pih

The ratio of their volume =
(volume of cylinder A)/(volume of cylinder B)

=
(9\pi h)/(20.25\pi h)

= 4:9

User Scott Cranfill
by
2.8k points