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Write the equation of the line parallel to y = 3x -5 and that passes through(1, -7).

User KaroluS
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Answer:

Explanation:

The line is parallel to y = 3x -5, meaning it has the same slope; therefore, we already know that our equation takes the form


y=3x+b

Now, the second requirement is that the line should pass through the point (1, -7), meaning it should satisfy the condition that when x = 1, y = -7. Putting in these values of x and y in the above equation gives


-7=3(1)+b
-7=3+b

subtracting 3 from both sides gives


-10=b

With the value of b in hand, we now have the equation of the line


\boxed{y=3x-10}

which is our answer!

User Manas Saxena
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